Seven years ago the ratio of the ages of A and B was 2 3 Three years hence the ratio of their ages w...........

Quantitative Aptitude (MTS) Problems based on Ages

Seven years ago, the ratio of the ages of A and B was 2 : 3. Three years hence, the ratio of their ages will be 5 : 7. The sum of

their present ages (in years) is:

This questions was previously asked in

SSC MTS 14th October 2021 Shift-3

114

118

112

110

- Initially, let's denote the ages of A and B seven years ago as 2x and 3x respectively, according to the given ratio.

- Thus, A's current age is 2x + 7 and B's current age is 3x + 7.

- In three years, their ages will be 2x + 10 and 3x + 10.

- The future age ratio given is 5:7. Set up the equation: (2x + 10) / (3x + 10) = 5 / 7.

- Solve this equation: 7(2x + 10) = 5(3x + 10).

- This simplifies to 14x + 70 = 15x + 50.

- Rearrange to find x: x = 20.

- Calculate present ages: A = 2x + 7 = 47 years, B = 3x + 7 = 67 years.

- The sum of their present ages is 114 years.

- Hence, the correct choice is Option 1: 114

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