If A and B can do a piece of work in 20 days and A alone can do the same work in 30 days then in how...........

Quantitative Aptitude (MTS) Time and work

If A and B can do a piece of work in 20 days,and A alone can do the same work in 30 days, then in how many days can B alone

complete the same work?

This questions was previously asked in

SSC MTS 12th October 2021 Shift-1

- Option 1: 60 Days

- Combined work efficiency of A and B is 1/20 of the work per day.

- A's individual work efficiency is 1/30 of the work per day.

- B's work efficiency can be calculated as: 1/20 - 1/30 = 1/60.

- Thus, B alone can complete the work in 60 days.

- Correct Answer: 60 Days

- Option 2: 40 Days

- This implies B can do the work faster, which conflicts with the given efficiency.

- Option 3: 75 Days

- This contradicts A's speed, as B is slower than A.

- Option 4: 50 Days

- B is slower than A, making this option incorrect.

Submit Error