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A train can travel 40% faster then a car.Both the train and the car start from point A at the same time and reach point B, which
is 70km away point from A,at the same time.On the way, however,the train lost about 15 minutes while stopping at stations.
The speed of the car in km/h is:
120
80
90
100
- Let the speed of the car be \( x \) km/h.
- Therefore, the speed of the train is 1.4 times faster, i.e., \( 1.4x \) km/h.
- The car travels 70 km in \(\frac{70}{x}\) hours.
- The train travels 70 km in \(\frac{70}{1.4x}\) hours but loses 15 minutes (0.25 hours) due to stops.
- The effective travel time for the train is \(\frac{70}{1.4x} + 0.25\).
- Since both reach point B simultaneously, \(\frac{70}{x} = \frac{70}{1.4x} + 0.25\).
- Solving, \(1.4 \times 70 = 70 + 0.25 \times 1.4x \).
- 98 = 70 + 0.35x, so 28 = 0.35x, giving \( x = 80 \).
- Option 2: 80 km/h is the correct speed of the car.
Option 2: 80 km/h is the correct answer.
By: santosh ProfileResourcesReport error
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