The sum of three numbers is 396 If the ratio between the first and the second number is 7 11 and tha...........

Quantitative Aptitude (MTS) Ratio, Proportion

The sum of three numbers is 396. If the ratio between the first and the second number is 7: 11 and that between the second

and the third number is 11 : 15. then the difference between the first and the third number is:

This questions was previously asked in

SSC MTS 7th October 2021 Shift-1

- We have three numbers, let's call them A, B, and C.

- Their sum is given as 396, i.e., A + B + C = 396.

- The ratio between A and B is 7:11, which means A/B = 7/11 or A = (7/11)B.

- The ratio between B and C is 11:15, which means B/C = 11/15 or C = (15/11)B.

- Substitute A and C in terms of B into the sum equation: (7/11)B + B + (15/11)B = 396.

- Simplify and solve for B: (33/11)B = 396, B = 132.

- Find A: A = (7/11) × 132 = 84.

- Find C: C = (15/11) × 132 = 180.

- The difference between A and C is 180 - 84 = 96.

So, the correct answer is:

- Option 3: 96

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