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A solid metal cube of edge 12 cm is immersed completely in water in a cylindrical vessel whose radius is 20 cm and height is 32
cm, and the water in the vessel is up to a height of 15 cm. The height (in cm) by which the water will rise in the vessel is (correct
to one decimal place):
0.9
1.4
1.2
1.1
- A solid metal cube with an edge of 12 cm is submerged in water.
- Volume of the cube = side³ = 12 cm × 12 cm × 12 cm = 1,728 cm³.
- This volume of the cube will displace an equal volume of water in the cylindrical vessel.
- The vessel's cross-sectional area = p × radius² = p × (20 cm)² = 400p cm².
- Rise in water height = displaced volume / vessel's cross-sectional area = 1,728 cm³ / 400p cm².
- Rise = 1,728 / (400p) = 1,728 / (1,256.64) = approximately 1.4 cm.
- Correct Answer: Option 2: 1.4
.
By: santosh ProfileResourcesReport error
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