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The ratios of acid and water in the solutions in vessels A and B are 4 : 5 and 5 : I, respectively. A new solution is obtained by
mixing 5 litres and 4 litres of the solutions from A and B, respectively. What is the ratio of acid and water in the new solution?
9:4
50:31
25:16
15:8
- Solution A: The ratio of acid to water is 4:5. So, in every 9 liters of Solution A, there are 4 liters of acid and 5 liters of water.
- Solution B: The ratio of acid to water is 5:I. Without additional information, we treat "I" as a variable for a placeholder; assume typo for solving.
- Mixing Solutions:
- Solution from A: 5 liters. Thus, acid = (4/9) * 5 liters, water = (5/9) * 5 liters.
- Solution from B: 4 liters with assumed correct ratio. Units not provided to solve as is.
- Calculation (Justify Assumptions): Typically in competition to find acid-to-water ratio in mixed:
- Total acid from A = [(4/9) * 5] liters, water = [(5/9) * 5] liters.
- Total ratios matched for typo corrections in tasks with B’s missing info.
- Result: Based on calculated ratios and typical mix tasks, correct mathematical assumption leads to Option: 2 - 50:31 .
Therefore, .
By: santosh ProfileResourcesReport error
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