A sum of 4 095 is divided between A B C and D such that the ratio of the shares of A and B is 1 3 th...........

Quantitative Aptitude (MTS) Ratio, Proportion

A sum of ?4,095 is divided between A, B, C and D such that the ratio of the shares of A and B is 1 : 3, that of B and C is 2 : 5 and

that of C and Dis 2 : 3. What is the difference (in ?) between the shares of B and D?

This questions was previously asked in

SSC MTS 6th October 2021 Shift-2

1,440

1,485

l,530

1,845

- We know the total sum is £4,095.

- The ratio of A to B is 1:3. This means if A's share is x, B's share is 3x.

- The ratio of B to C is 2:5. Let B's share be 2y, then C's share is 5y. Since B's share is represented by both x and y, equate them: 3x = 2y.

- The ratio of C to D is 2:3. So, if C's share is 2z, D's share is 3z. This gives: 5y = 2z.

- Solve these equations:

- From 3x = 2y, we find y = 1.5x.

- From 5y = 2z, we find z = 2.5y = 3.75x.

- The shares in terms of x: A = x, B = 3x, C = 7.5x, D = 11.25x.

- The sum of all shares: x + 3x + 7.5x + 11.25x = 22.75x.

- Make this equal to total sum 4095: 22.75x = 4095. Therefore, x = 180.

- Substitute back to find individual shares:

- A = 180

- B = 540

- C = 1350

- D = 2025

- The difference between the shares of B and D: 2025 - 540 = 1485.

- ?? Option 2: 1,485 is the correct difference.

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