A thief escapes custody at 10 a m He runs at a speed of 40 km h The policeman starts chasing the thi...........

Quantitative Aptitude (MTS) Time & distance

A thief escapes custody at 10 a.m. He runs at a speed of 40 km/h. The policeman starts chasing the thief at 11:30 a.m.,

starting from the point from where the thief escaped custody. The speed of the policeman is 60 km/h. At what time will he

catch the thief?

This questions was previously asked in

SSC MTS 21st July 2022 Shift-2

2:45 p.m.

2:00 p.m.

2:15 p.m.

2:30 p.m.

- The thief escapes at 10 a.m. and runs at 40 km/h.

- By 11:30 a.m., he has run for 1.5 hours, covering a distance of 60 km (40 km/h * 1.5 hours).

- The policeman starts chasing from the same point at 11:30 a.m. at 60 km/h.

- The policeman's speed exceeds the thief's speed by 20 km/h (60 km/h - 40 km/h).

- The policeman needs to cover the 60 km gap between them.

- Time taken by the policeman to catch the thief is Distance/Relative Speed = 60 km/20 km/h = 3 hours.

- Starting from 11:30 a.m., the policeman will catch the thief at 2:30 p.m.

- Option 4: 2:30 p.m. is correct.

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