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If 3a: 2b = (6a - 3 : (3b - 2) and a = b - 1, then what will be the value of 12ab?
28
24
30
32
Given: 3a: 2b (6a3): (3b-2) a=b-1 To find: The value of 12ab Explanation We can begin by substituting the given value of a in terms of b into the equation for 3(b-1): 2b = (6(b-1)-3): (3b-2) Simplifying this equation, we get: (3b-3): 2b = (6b-9): (3b-2) We can now cross-multiply to eliminate the denominators and simplify: => (3b-3)(3b-2) = (6b-9)2b 9b2-15b+ 6 = 12b2 - 18b 3b23b60 b2-b-2=0 ⇒ (b-2)(b + 1) = 0 So, b = 2 or b = -1. If b = 2, then a = b - 1 = 1, and we can find the value of 12ab as: 12ab = 12 x 1 x 2 = 24 If b = -1, then a = b - 1 = -2, and we can find the value of 12ab as: 12ab = 12 x (-2) x (-1) = 24 Therefore, the value of 12ab is 24.
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