J1 can do a piece of work alone in 10 days J2 can do the same work alone in 12 days while ...........

Quantitative Aptitude (MTS) Time and work

J₁can do a piece of work alone in 10 days, J₂can do the same work alone in 12 days, while J₃can do it alone in 15 days. They

work together and complete the work, and receive a total of Rs2,250 for doing the work. What is the

difference in the shares of J₁and J₃?

This questions was previously asked in

SSC MTS 11th July 2022 Shift-2

Rs400

Rs300

Rs350

Rs450

- Let’s find their one day work rates:

- J1: 1/10 per day

- J2: 1/12 per day

- J3: 1/15 per day

- Combined one day work: 1/10 + 1/12 + 1/15 = (6 + 5 + 4) / 60 = 15/60 = 1/4 of work per day

- So, they finish the work in 4 days.

- J1’s total work: 4 × 1/10 = 2/5 of work

- J2’s total work: 4 × 1/12 = 1/3

- J3’s total work: 4 × 1/15 = 4/15

- Total shares (in Rs):

- J1: (2/5) × 2250 = Rs900

- J3: (4/15) × 2250 = Rs600

- Difference: Rs900 - Rs600 = Rs300

- Option:2 Rs300 is correct.

- Other options (Rs400, Rs350, Rs450) do not match the calculated difference.

Correct Answer: Option:2 – Rs300

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