In a 100 m race A beats B by 20 m and B beats C by 5 m In the same race A beats C by ........

Quantitative Aptitude (MTS) Time & distance

In a 100-m race, A beats B by 20 m and B beats C by 5 m. In the same race, A beats C by:

This questions was previously asked in

SSC MTS 11th July 2022 Shift-1

24 m

22 m

26 m

25 m

- When A finishes 100 m, B has covered 80 m (A beats B by 20 m).

- So, B’s speed is 80% of A’s speed.

- When B runs 100 m, C has covered 95 m (B beats C by 5 m).

- So, C’s speed is 95% of B's speed.

- C’s speed relative to A = 0.8 × 0.95 = 0.76 (76% of A’s speed).

- So, when A finishes 100 m, C covers 76 m.

- Therefore, A beats C by 24 m (100 m - 76 m).

Option 1: 24 m – Correct

- Option 2: 22 m – Incorrect

- Option 3: 26 m – Incorrect

- Option 4: 25 m – Incorrect

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