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The weight of seven women W1, W2, W3, W4, W5, W6 and W7 are compared. The weight of W4 is more than W7. The weight of
W5 is more than only three women and the weight of W2 is less than only W1 and W3. If the weight of W7 is the lowest, then
the minimum number of women who have weight more than W6 is?
3
1
4
2
Correct option 3: 4
Given: Seven women W1, W2, W3, W4, W5, W6 and W7. 1) If the weight of W7 is the lowest. 2) The weight of W5 is more than only three women and the weight of W2 is less than only W1 and W3. Case 1: W3 > W1 > W2 > W5 >_>_> W7 Case II: W1 > W3 > W2> W5 >>> W7 The weight of W4 is more than W7. And, Height of W6 is smaller than W5 (Only condition left) Case 1: W3 > W1 > W2> W5 W6 > W4 > W7 Case II: W1 > W3 > W2> W5 > W4 > W6 > W7 Here, in Case I, there are minimum Four women who have weight more than W6. And, in Case II, there are maximum Five women who have weight more than W6. So, the minimum number of women who have weight more than W6 is 4. Hence, the correct answer is "Option 2".
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