Two vessels of equal capacity and both completely filled contain mixtures of milk and water in the r...........

Quantitative Aptitude (MTS) Mixture and Alligation

Two vessels of equal capacity, and both completely filled, contain mixtures of milk and water in the ratio of 5 : 1 and 6 : 5,

respectively. Both the mixtures are now mixed thoroughly. What is the ratio of milk to water in the new mixture so obtained?

This questions was previously asked in

SSC MTS 13th July 2022 Shift-3

105 : 67

57 : 41

91 : 41

28 : 43

- First vessel's mixture ratio is 5 milk:1 water. Total parts = 5 + 1 = 6.

- So, milk = 5/6 of its content and water = 1/6 of its content.

- Second vessel's mixture ratio is 6 milk:5 water. Total parts = 6 + 5 = 11.

- Thus, milk = 6/11 of its content and water = 5/11 of its content.

- Both vessels are of equal capacity, let's assume 'C' liters.

- First vessel: Milk = \( \frac{5C}{6} \), Water = \( \frac{C}{6} \).

- Second vessel: Milk = \( \frac{6C}{11} \), Water = \( \frac{5C}{11} \).

- Combined milk = \( \frac{5C}{6} + \frac{6C}{11} = \frac{91C}{66} \).

- Combined water = \( \frac{C}{6} + \frac{5C}{11} = \frac{41C}{66} \).

- Hence, new milk to water ratio is 91:41.

- 1. 105:67 is incorrect based on calculation.

- 2. 57:41 doesn't match the derived ratio.

- 3. 91:41 matches the calculated outcome.

- 4. 28:43 does not align with derived ratio.

Submit Error