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There are two numbers such that the first number is three times of the second number. If the average of these two numbers is
72, then what is the first number?
108
54
36
64
- Let's call the second number "x".
- The first number is three times the second number, so it's "3x".
- The average of the two numbers is given as 72.
- So, we write the equation for the average: (x + 3x)/2 = 72.
- Simplify the equation: 4x/2 = 72 ? 2x = 72 ? x = 36.
- The first number "3x" thus becomes 3 * 36 = 108.
- Therefore, the first number is 108.
- Option:1, 108
- Option:2, 54
- Option:3, 36
- Option:4, 64
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