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What is the sum of the digits of the least number, which when divided by 15. 15 and 27 leaves the same remainder 9 in each case and
is also completely divisible by 11 ?
20
17
18
19
To find the least number that satisfies the given conditions:
- The number leaves a remainder of 9 when divided by 12, 15, and 27.
- Therefore, it can be expressed as 9 more than the least common multiple of these numbers.
Steps involved:
- Calculate the least common multiple (LCM) of 12, 15, and 27.
- The prime factorization of 12 is 2^2 * 3.
- The prime factorization of 15 is 3 * 5.
- The prime factorization of 27 is 3^3.
- LCM is 2^2 * 3^3 * 5 = 540.
- The least number is 540 + 9 = 549.
- The sum of the digits of 549 is 5 + 4 + 9 = 18.
- Verify that 549 is divisible by 11, which it is (the alternating sum of digits is 0, which is divisible by 11).
Option 3 is correct.
- Option 3: 18 is the correct answer.
.
By: santosh ProfileResourcesReport error
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