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A tank is filled in 4 hours by three pipes A, B and C. The pipe C is twice as fast as B and pipe B is thrice as fast as A. How much time
will pipe A alone take to fill the tank?
25 hours
40 hours
30 hours
32 hours
- The tank is filled in 4 hours by pipes A, B, and C working together.
- Let the rate of pipe A be x.
- Pipe B, being three times faster, has a rate of 3x.
- Pipe C, being twice as fast as B, has a rate of 6x.
- The combined rate of all three pipes (A + B + C) is x + 3x + 6x = 10x.
- In 4 hours, the total work done is 1 tank.
- Hence, 4 hours × 10x = 1 tank ? x = 1/40 tank/hour.
- Therefore, pipe A alone would take 40 hours to fill the tank.
- The correct answer is Option: 2, 40 hours.
By: santosh ProfileResourcesReport error
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