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The lengths of the parallel sides of a trapezium are 51 cm and 21 cm, and that of each ofthe other two sides is 39 cm. What is the
area (in cm2) of the trapezium?
1260
1296
1152
1206
Here are the details for calculating the area of the trapezium:
- This trapezium is isosceles because the non-parallel sides are equal (39 cm each).
- We calculate the height using coordinate geometry or the Pythagorean theorem by dropping perpendiculars from the ends of one parallel side to the other.
- The distance between the parallel sides (base) can be seen as the solid base for height calculations.
- By dropping heights, using the properties of an isosceles trapezium, these perpendiculars divide the trapezium into a rectangle and two right-angled triangles.
- The height (h) can be calculated using the Pythagorean theorem where \( h^2 + \left(\frac{51 - 21}{2}\right)^2 = 39^2\).
Calculate:
$$ h^2 + 15^2 = 39^2 $$
$$ h^2 + 225 = 1521 $$
$$ h^2 = 1296 $$
$$ h = 36 \, \text{cm} $$
- Area formula for trapezium: \( \text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height} \).
$$ \text{Area} = \frac{1}{2} \times (51 + 21) \times 36 $$
$$ \text{Area} = \frac{1}{2} \times 72 \times 36 $$
$$ \text{Area} = 36 \times 36 = 1296 \, \text{cm}^2 $$
- Correct Answer: Option 2, 1296
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By: santosh ProfileResourcesReport error
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