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As observed from the top of a lighthouse, 45 m high above the sea-level, the angle of depression of a ship, sailing directly towardsit,
changes from 30o to 45o. The distance travelled by the ship during the period of observation is: (Your answer
should be correct to one decimalplace.)
32.9 m
33.4 m
36.9 m
24.8 m
Let’s break this down:
- You’ve got a lighthouse, 45 m high. The ship’s out at sea. The angles of depression to the ship change from 30° to 45° as it moves.
- Picture two right triangles, both using the lighthouse as the vertical leg (45 m), but with their bases at different distances (let’s call them x and y).
- For the 30° angle:
tan(30°) = 45 / x
So, x = 45 / tan(30°) = 45 / (1/v3) = 45 * v3 ˜ 77.94 m
- For the 45° angle:
tan(45°) = 45 / y
So, y = 45 / 1 = 45 m
- The ship travels the difference:
Distance = x - y = 77.94 - 45 = 32.94 m
- Rounded to one decimal, that’s 32.9 m.
- Option 1: 32.9 m
- Option 2: 33.4 m
- Option 3: 36.9 m
- Option 4: 24.8 m
No need to overthink it. Here’s the real deal:
OPTION 1 is correct.
By: santosh ProfileResourcesReport error
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