send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A field is in the shape of a rectangle of length 90 m and breadth 75 m. In one corner of the field, a pit, which is 18 m long 15 m
broad and 6 m deep, has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. Find the
rise in the level of the field?
27 cm
25 cm
28 cm
24 cm
Let’s break down the problem:
- Area of field = 90 m × 75 m = 6750 m²
- Pit size = 18 m × 15 m × 6 m
? Volume dug out = 18 × 15 × 6 = 1620 m³
- Area minus pit = (6750 – 270) m² = 6480 m²
- The earth (1620 m³) is spread evenly over 6480 m².
- Rise in level = Volume spread / Area covered
= 1620 m³ / 6480 m² = 0.25 m = 25 cm
So, the correct option is:
- Option 2: 25 cm
Other options:
- 27 cm, 28 cm, and 24 cm do not match the calculation.
- Therefore, Option 2 is the only correct choice.
By: santosh ProfileResourcesReport error
Access to prime resources
New Courses