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Solve $$\left\{1 + 7 + \left(16 \div 8 \div 2\right)\right\} + \left\{\left(6 \times 2^{2} + 6\right) \times \frac{2}
{\sqrt{36}}\right\}$$
17
21
19
12
To solve the problem, we break it into simpler parts:
- Inside the first bracket:
- \( 16 \div 8 \div 2 = 1 \)
- Thus, the first bracket simplifies to \( 1 + 7 + 1 = 9 \).
- Inside the second bracket:
- \( 6 \times 2^2 + 6 = 6 \times 4 + 6 = 24 + 6 = 30 \)
- \(\sqrt{36} = 6\), so \(\frac{2}{\sqrt{36}} = \frac{2}{6} = \frac{1}{3}\)
- So, \(30 \times \frac{1}{3} = 10\).
- Add the results from both brackets: \(9 + 10 = 19\).
- Option:3, 19 is correct.
By: santosh ProfileResourcesReport error
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