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If a 4 digit number x58y is exactly divisible by 9, then the least value of (x + y) is:
4
5
3
2
To determine if a number is divisible by 9, the sum of its digits must be divisible by 9. Let's analyze:
- The number is represented as x58y.
- The sum of its digits is \(x + 5 + 8 + y\).
- Simplifying, it's \(x + y + 13\).
- We need \(x + y + 13\) to be divisible by 9.
Let's find the smallest possible value of \(x + y\):
1. If \(x + y = 5\), then \(x + y + 13 = 18\) which is divisible by 9.
2. Any smaller value, such as 4 or 3, results in sums that are not divisible by 9.
Therefore, the least value of \(x + y\) that satisfies this condition is 5.
- Correct Answer: Option 2: 5
By: santosh ProfileResourcesReport error
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