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Two posts are 4 m apart. Both posts are on same side of a tree. If the angles of depressions of these posts when observed from the top of the tree are 45o and 60o respectively, then what is the height of the tree?
√3 + 1
√3(√3 + 1)
2(√3 + 1)
4√3(√3 + 1)
Let's break down the problem:
- Let the height of the tree be *h* meters.
- Let the distances from the foot of the tree to posts A and B be *x* and *x + 4* meters.
- From the top of the tree, angles of depression are 45° (to A) and 60° (to B).
Using tan(?) = opposite/adjacent:
- For post A: tan 45° = h / x ? h = x
- For post B: tan 60° = h / (x + 4) ? v3 = h / (x + 4) ? h = v3(x + 4)
Set equal since h = x:
x = v3(x + 4)
x = v3x + 4v3
x - v3x = 4v3
x(1 - v3) = 4v3
x = 4v3 / (1 - v3)
Rationalize denominator:
x = 4v3(1 + v3) / [(1 - v3)(1 + v3)]
= 4v3(1 + v3) / (1 - 3)
= 4v3(1 + v3) / (-2)
= -2v3(1 + v3)
But *x* must be positive; take modulus:
x = 2v3(v3 + 1)
So, h = x = 2(v3 + 1) meters
Summary of options:
- Option 1: v3 + 1 (too small, not correct)
- Option 2: v3(v3 + 1) (missing factor of 2, not correct)
- Option 3: 2(v3 + 1) correct value
- Option 4: 4v3(v3 + 1) (too large)
Final answer:
Option 3: 2(v3 + 1) — this is the correct answer!
By: Parvesh Mehta ProfileResourcesReport error
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