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In ΔABC, a line parallel to side BC cuts the side AB and AC at points D and E respectively and also point D divide AB in the ratio of 1 : 4. If area of ΔABC is 200 cm2, then what is the area (in cm2) of quadrilateral DECB?
192
90
120
96
- A line parallel to side BC of ?ABC intersects sides AB and AC at points D and E.
- The point D divides AB in the ratio 1:4, meaning AD/DB = 1/4.
- The area of ?ABC is given as 200 cm².
- Since DE || BC, triangles ADE and ABC are similar.
- Since AD:DB = 1:4, thus area of ?ADE : area of ?ABC = (1/5)² = 1/25.
- Area of ?ADE = (1/25) * 200 = 8 cm².
- Area of quadrilateral DECB = Area of ?ABC - Area of ?ADE = 200 - 8 = 192 cm².
Correct Answer: Option 1 - 192 cm²
By: Kamal Kashyap ProfileResourcesReport error
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