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Three spherical balls of radius 2 cm, 4 cm and 6 cm are melted to form a new spherical ball. In this process there is a loss of 25% of the material. What is the radius (in cm) of the new ball?
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- The volume of a sphere is calculated using the formula: \( V = \frac{4}{3} \pi r^3 \).
- For the first ball (radius 2 cm): Volume = \( \frac{4}{3} \pi (2)^3 \).
- For the second ball (radius 4 cm): Volume = \( \frac{4}{3} \pi (4)^3 \).
- For the third ball (radius 6 cm): Volume = \( \frac{4}{3} \pi (6)^3 \).
- Calculate the total initial volume by adding all three volumes.
- Account for the 25% material loss, keeping only 75% of the initial total volume.
- Use the remaining volume to find the radius of the new ball using \( r = \left(\frac{3V}{4\pi}\right)^{\frac{1}{3}} \).
- Solving results in a new radius of 6 cm.
Option 1: 6 cm
- Correct Answer: Option 1: 6 cm.
- .
By: Kamal Kashyap ProfileResourcesReport error
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