A man driving at 2 3rd of his original speed reaches his destination 30 minutes later than the usual...........

Quantitative Aptitude (CPO) Time & distance

A man driving at 2/3rd of his original speed reaches his destination 30 minutes later than the usual time. Then the usual time is:

45 minutes

90 minutes

60 minutes

120 minutes

- Let's denote the usual time to reach the destination as \( T \) minutes.

- If the man drives at \(\frac{2}{3}\) of his original speed, he takes 30 minutes longer.

- So, the equation becomes: \(\frac{3}{2}T = T + 30\).

- Solving this, we get: \(\frac{T}{2} = 30 \Rightarrow T = 60\).

- Option 1: 45 minutes

- Would imply taking 67.5 minutes at reduced speed.

- Results in a difference of 22.5 minutes, not 30.

- Option 2: 90 minutes

- Would imply taking 135 minutes at reduced speed.

- That’s a 45-minute difference, off by 15 minutes.

- Option 3: 60 minutes

- Correct calculation: 90 minutes at reduced speed.

- Matches the 30-minute difference.

- Option 4: 120 minutes

- Results in 180 minutes at reduced speed.

- A difference of 60 minutes, not 30.

Correct Answer: Option 3: 60 minutes

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