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An earthing wire connected to the top of an electricity pole has its other end inside the ground. The foot of the wire is 1.5 m away from the pole and the wire is making an angle of 60° with the level of the ground. Determine the length of wire.
2 m
3 m
√3 m
√3/2 m
- We have a right-angled triangle formed by the pole, the wire, and the distance from the pole to the foot of the wire.
- The wire is the hypotenuse of the triangle.
- The angle between the wire and the ground is 60°.
- The adjacent side (distance from the pole) is 1.5 m.
- We use the cosine function: \(\cos 60° = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{1.5}{\text{length of wire}}\).
- \(\cos 60° = \frac{1}{2}\), so \(\frac{1}{2} = \frac{1.5}{\text{length of wire}}\).
- Solving for the length of the wire gives: \(\text{length of wire} = 1.5 \times 2 = 3 \, \text{m}\).
- Correct Answer: Option 2, 3 m
By: Parvesh Mehta ProfileResourcesReport error
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