send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The angles of elevation of the top of a building from the top and bottom of a tree are 30° and 60° respectively. If the height of the tree is 50 m, then what is the height of the building?
Options:
50√3
75
50(√3 + 1)
75√3
Let's break it down stepwise:
- Let's say building height = h, tree height = 50 m.
- Let both stand on the same level, separation between tree and building = d metres.
- From the top of the tree, angle of elevation to the top of the building = 30°
? tan 30° = (h - 50)/d ? 1/v3 = (h - 50)/d ? d = v3(h - 50)
- From the bottom of the tree, angle of elevation to top of building = 60°
? tan 60° = h/d ? v3 = h/d ? d = h/v3
- Set d = v3(h - 50) = h/v3
? Cross-multiplied: v3(h - 50) = h/v3
? 3(h - 50) = h
? 3h - 150 = h
? 2h = 150
? h = 75
- Option 1: 50v3 — Incorrect
- Option 2: 75 — Correct!
- Option 3: 50(v3 + 1) — Incorrect
- Option 4: 75v3 — Incorrect
By: Kamal Kashyap ProfileResourcesReport error
Access to prime resources
New Courses