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Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
321 : 213 : 123
432 : 324 : 231
798 : 897 : 798
. 564 : 645 : 456
Let’s walk through each option and see what’s going on:
- Option 1: 321 : 213 : 123
- Take a look, these numbers are all rearrangements of one another—they’re anagrams with digits. Mix up 321, you can get 213 or 123.
- Option 2: 432 : 324 : 231
- Similar concept: Try to rearrange 432. You can get 324, but 231 isn’t a rearrangement of those same digits (the digits 4 doesn’t appear).
- Option 3: 798 : 897 : 798
- These are definitely rearrangements or repeats. 798 and 897 use the same digits, and 798 appears twice.
- Option 4: 564 : 645 : 456
- Again, easy to see—all the same digits, just shuffled.
Here’s the thing, Option 2 stands out because 231 doesn’t fit in with the other two (432 and 324); it throws in a 2 but drops the 4, breaking the pattern.
Answer:
Option 2 is the odd one out.
By: Kamal Kashyap ProfileResourcesReport error
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