send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The average of 11 results is 182. If the average of first 6 results is 199 and that of the last 6 results is 161, then what will be the 6th result?
Options:
79
118.5
158
237
- The average of 11 results is 182, which means the total of these results is \(11 \times 182 = 2002\).
- The average of the first 6 results is 199, so their sum is \(6 \times 199 = 1194\).
- The average of the last 6 results is 161, so their total is \(6 \times 161 = 966\).
- Since the 6th result overlaps in both the first and last 6 results, it is counted twice in these sums.
- Therefore, the equation becomes: \(1194 + 966 - 6x = 2002\).
- Simplifying: \(2160 - 6x = 2002\).
- Now, solving for \(x\):
- \(6x = 2160 - 2002\)
- \(6x = 158\)
- \(x = 158/6 = 158\).
- After matching with the options, the correct answer is Option 3: 158.
By: Kamal Kashyap ProfileResourcesReport error
Access to prime resources
New Courses