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A chord of length 7 cm subtends an angle of 60° at the centre of a circle. What is the radius (in cm) of the circle?
Options:
7√2
7√3
7
14
- To find the radius \( r \) of a circle when a chord of length \( 7 \) cm subtends a \( 60^\circ \) angle at the center:
- Use the formula: chord length \( = 2r \sin(\theta/2) \), where \( \theta \) is in degrees.
- Here, \( 7 = 2r \sin(30^\circ) \).
- Since \( \sin(30^\circ) = \frac{1}{2} \), the equation becomes: \( 7 = 2r \times \frac{1}{2} \).
- \( 2r \times \frac{1}{2} = r \) so \( 7 = r \).
- Therefore, the radius is 7 cm.
- Option 1: \( 7\sqrt{2} \) ? Not correct; comes if angle or chord is different.
- Option 2: \( 7\sqrt{3} \) ? Not correct; possible if angle was \( 120^\circ \).
- Option 3: 7 Correct answer.
- Option 4: 14 ? Not correct; would require a sine of \( 0.5 \) for a much longer chord.
By: Kamal Kashyap ProfileResourcesReport error
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