In Delta ABC ang BCA 90 deg AC 24 cm and BC 10 cm What is the radius in cm of the circum circle of D...........

Quantitative Aptitude (CPO) Geometry

In ΔABC, ∠BCA = 90°, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circum-circle of ΔABC?

Options:

12.5

- In a right-angled triangle, the circumcircle's radius (R) is half the hypotenuse.

- For ?ABC, angle ?BCA is 90°, so AB is the hypotenuse.

- Use the Pythagorean theorem: AB² = AC² + BC².

- AB² = 24² + 10² = 576 + 100 = 676.

- Calculate AB: AB = v676 = 26 cm.

- The radius of the circumcircle (R) is half of AB: R = 26/2 = 13 cm.

- Your answer is option 2, which is 13 cm.

- Correct Answer: Option: 2, 13 cm

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