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If 2cos2 θ - 1 = 0 and θ is acute, then what is the value of (cot2 θ - tan2 θ)?
0
2
10/3
1
Let’s walk through this step by step:
- Start with the equation:
2cos²? - 1 = 0
2cos²? = 1 ? cos²? = ½ ? cos? = 1/v2 (since ? is acute, cos? is positive)
- Now, sin²? + cos²? = 1 ? sin²? = 1 - ½ = ½ ? sin? = 1/v2
- So, tan? = sin?/cos? = (1/v2)/(1/v2) = 1
cot? = 1/tan? = 1
- You need cot²? - tan²?:
cot²? = 1, tan²? = 1, so cot²? - tan²? = 1 - 1 = 0
Let’s check the options:
- Option 1: 0 — This is correct.
- Option 2: 2 — Nope, we just found 0.
- Option 3: 10/3 — No.
- Option 4: 1 — Not right either.
Answer:
What this means: With the values sorted out, only 0 fits perfectly. No other option makes sense based on the math. There’s no need to overthink, just keep it clear and straightforward.
By: Parvesh Mehta ProfileResourcesReport error
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