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In ΔPQR, a line parallel to side QR cuts the side PQ and PR at points M and N respectively and point M divide PQ in the ratio of 1 : 2. If area of ΔPQR is 360 cm2, then what is the area (in cm2) of quadrilateral MNRQ?
160
320
120
96
Let’s break it down:
- We’ve got triangle PQR. A line parallel to QR slices across from PQ at M and from PR at N.
- Point M splits PQ in a 1:2 ratio (so PM:PQ = 1:3 total).
- When a triangle is cut by a line parallel to its base, it chops off a smaller triangle that’s similar to the whole triangle.
- The area ratio of these similar triangles matches the square of the ratio of their sides.
- Here, PM/PQ = 1/3, so the area of triangle PMN is (1/3)^2 = 1/9 of the big triangle.
- Total area = 360 cm². So area of PMN = 360 × (1/9) = 40 cm².
- The area of quadrilateral MNRQ = area of ?PQR – area of ?PMN = 360 – 40 = 320 cm².
Let’s look at the options:
- Option 1 (160 cm²): Nope, too small.
- Option 2 (320 cm²): Yes, that’s exactly right.
- Option 3 (120 cm²): Not matching the math.
- Option 4 (96 cm²): Too low.
?? Correct answer: Option 2 — 320 cm².
By: Parvesh Mehta ProfileResourcesReport error
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