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A cylindrical well of height 40 metres and radius 7 metres is dug in a field 56 metres long and 11 metres wide. The earth taken out is spread evenly on the field. What is the increase in the level of the field?
12.5
10.66
11.5
13.33
Correct 4: 13.33
Let increase in level is h. In all process volume of earth remains same =, So, Volume of well = (Volume of field - Volume of well opening) ? × 72 × 40 = [56 x 11x h - ? x 72 x h] ? × 72 × 40 = [(56 x 11) - (π x 72)] x h 22/7 x 49 x 40 = (616 - 22/7 x 49) x h 6160= (616 - 154) h h = 6160/462 = 13.33
By: Parvesh Mehta ProfileResourcesReport error
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