In Delta PQR ang PQR 90 deg PQ 5 cm and QR 12 What is the radius in cm of the circum circle of Delta...........

Quantitative Aptitude (CPO) Mensuration 2D

In ΔPQR, ∠PQR = 90°, PQ = 5 cm and QR = 12. What is the radius (in cm) of the circum-circle of ΔPQR?

6.5

7.5

- In a right-angled triangle, the hypotenuse is the diameter of the circum-circle.

- Here, ?PQR = 90° means the right angle is at Q.

- The hypotenuse PR can be found using the Pythagorean theorem:

PR = \sqrt{PQ^2 + QR^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13

- The diameter of the circum-circle is 13 cm.

- Therefore, the radius of the circum-circle is half of the hypotenuse:

\text{Radius} = \frac{13}{2} = 6.5

- Correct Answer: Option 1 - 6.5

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