Ruksana travelled at 60 km h while going from point A to point B and returned via the same route at ...........

Quantitative Aptitude (CHSL) Time & distance

Ruksana travelled at 60 km/h while going from point A to point B, and returned via the same route at a different speed. If

Ruksana’s overall average speed during the two-way journey was 48 km/h, what was her speed while travelling from B to A?

This questions was previously asked in

SSC CHSL 2nd June 2022 Shift-2

40 km/h

36 km/h

42 km/h

45 km/h

- Ruksana's average speed for the entire journey is given as 48 km/h.

- She traveled at 60 km/h from A to B.

- We need to find her speed on the return trip from B to A.

- We use the formula for average speed:

\text{Average speed} = \frac{2ab}{a+b}

where \( a \) is the speed from A to B and \( b \) is the speed from B to A.

- Plugging in the values:

48 = \frac{2 \times 60 \times b}{60 + b}

- Solving for \( b \), we find \( b = 40 \) km/h.

- Thus, Ruksana's speed from B to A was 40 km/h.

Correct Answer: Option 1: 40 km/h

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