In an election that was contested by 2 candidates one candidate got 20 of the total votes and yet lo...........

Quantitative Aptitude (CHSL) Percentage

In an election that was contested by 2 candidates, one candidate got 20% of the total votes and yet lost by 600 votes. What is

the total number of votes cast in the election, assuming all votes are valid?

This questions was previously asked in

SSC CHSL 6th June 2022 Shift-1

900

700

800

1000

- Let's denote the total number of votes as \( V \).

- One candidate received 20% of the votes, which is \( 0.2V \).

- The opponent received the remaining 80% of the votes, \( 0.8V \).

- The candidate with 20% of the votes lost by 600 votes.

- This means the opponent had 600 more votes than the losing candidate.

- So, \( 0.8V - 0.2V = 600 \).

- Simplifying gives \( 0.6V = 600 \).

- Solving for \( V \) gives \( V = 1000 \).

- Option 1: 900

- Doesn't satisfy the equation \( 0.6V = 600 \).

- Option 2: 700

- Doesn't satisfy the equation \( 0.6V = 600 \).

- Option 3: 800

- Doesn't satisfy the equation \( 0.6V = 600 \).

- Option 4: 1000

- Satisfies \( 0.6 \times 1000 = 600 \).

Therefore, the total number of votes cast is 1000.

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