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There is a continuous growth in the population of a village at the rate of 5% per annum. If its present population is 18522, what
was the population of the village 3 years ago?
17500
16400
16000
17200
- The population growth rate is 5% per annum.
- The current population of the village is 18,522.
- We need to find the population 3 years ago.
- Use the formula for reverse compound growth:
$$ \text{Past Population} = \frac{\text{Present Population}}{(1 + \text{Growth Rate})^n} $$
- For 3 years with a growth rate of 5%, the formula becomes:
$$ \frac{18,522}{(1.05)^3} $$
- Calculate \( (1.05)^3 \) which gives approximately 1.157625.
- Divide 18,522 by 1.157625 to find the past population.
- This calculation gives us approximately 16,000.
- Option 3 (16,000) is correct.
- Options 1, 2, and 4 do not match the calculated value.
By: santosh ProfileResourcesReport error
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