After seeing a policeman from a distance of 500 m a thief starts running at a speed of 10 km h After...........

Quantitative Aptitude (CHSL) Time & distance

After seeing a policeman from a distance of 500 m, a thief starts running at a speed of 10 km/h. After noticing, the policeman

chases immediately with a speed of 12 km h, and the thief is caught. The distance run by the policeman is:

This questions was previously asked in

SSC CHSL 10th June 2022 Shift-3

3.6 km

2.5 km

3 km

2.4 km

- The thief starts running when he sees the policeman from a distance of 500 meters.

- The thief runs at a speed of 10 km/h, which is approximately 2.78 meters per second.

- The policeman immediately starts chasing at a speed of 12 km/h, roughly 3.33 meters per second.

- The relative speed of the policeman with respect to the thief is 12 km/h - 10 km/h = 2 km/h.

- Converting this relative speed to meters per second gives approximately 0.56 meters per second.

- The time it takes for the policeman to catch the thief is when the distance between them (500m) is covered at the relative speed.

- Time = Distance / Relative Speed = 500m / 0.56 m/s = 892.86 seconds.

- The distance run by the policeman during this time is calculated by multiplying his speed (in m/s) by the time in seconds.

- Distance = Speed * Time = 3.33 m/s * 892.86 seconds = 2974.3 meters ˜ 3 km.

- Option 3: 3 km is the correct answer.

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