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RA and RB are two tangents from a common point ‘R’ outside the circle with centre ‘O’, having a radius of 6 cm. If ∠ARB = 70°,
find the measure of the angle AOB.
130o
110o
120o
80o
- When two tangents are drawn from an external point to a circle, they are equal in length. Therefore, ?ORA and ?ORB are isosceles triangles.
- The angles at the centres, ?OAR and ?OBR, are both right angles because tangents are perpendicular to the radius at the point of contact.
- In quadrilateral OARB, the sum of the angles is 360°.
- Using the property of tangents from an external point, ?OAR = ?OBR = 90°.
- So, ?AOB = 360° - ?ARB - ?OAR - ?OBR = 360° - 70° - 90° - 90° = 110°.
Therefore, Option 2: 110° is correct.
By: santosh ProfileResourcesReport error
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