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Two parallel chords are drawn in a circle of diameter 10 m. The length of one chord is 8 m and the distance between the two
chords is 6 m. Find the length of the other chord.
10 m
6 m
4 m
8 m
- The diameter of the circle is 10 m, so its radius (r) is 5 m.
- Chord 1 is 8 m long. Its distance from the center is found using the formula:
\( d_1 = \sqrt{r^2 - (l_1/2)^2} = \sqrt{5^2 - 4^2} = \sqrt{25 - 16} = 3 \) m.
- Two parallel chords are 6 m apart. So, the distance from the center to chord 2:
\( d_2 = 6 - d_1 = 6 - 3 = 3 \) m, but this would only be if the chords are on the same side from the center, which is not possible as the answer would repeat length or have negative value.
- The other chord is also at 3 m from the center (opposite side), so its length:
\( l_2 = 2\sqrt{r^2 - d_2^2} = 2\sqrt{25 - 9} = 2 \times 4 = 8 \) m.
- Therefore, the correct answer is:
- Option:4- 8 m
- Other options:
- Option:1- 10 m — Not possible, as that's the diameter.
- Option:2- 6 m — Not supported by calculations.
- Option:3- 4 m — Too short.
- So, the correct answer is Option:4- 8 m.
By: santosh ProfileResourcesReport error
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