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The sum of the squares of three numbers is 336 and the ratio of the first and the second as also of the second and the third is 1 : 2. Then find the difference of third and first number?
10
12
14
16
Let the number be x, 2x, 4x
According to the question,
x2+4x2+16x2=336
21x2=336
x2=16
x=4
Required difference = 16 - 4= 12
HENCE THE CORRECT ANSWER IS OPTION 2.
By: Himani Bihagra ProfileResourcesReport error
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