Explanation:

Let’s break down the information:

- S: S > Q, S < U

- P: P > S, P < R, P < U

- T: T > R

- The marks in ascending order: Q < S < P < R < T/U/U/R/T ?

- U < 69

- Third lowest marks = 56

- R = P + 12

- Q + R = 111

- P + T = 137

Let's assign the order:

Q < S < P < R < T (since P < R < T and S < P < R)

U: U is higher than S and P, but below 69. Since U could be above R or below T, but it's not the highest (cannot be T).

Let’s use variables:

Q, S, P, R, T, U

Assume numbers:

Since third lowest is 56, order is:

(1) Q

(2) S

(3) P = 56

(4) R

(5) T

(U somewhere above S and below 69, and above P)

Let’s step by step:

- If P = 56, R = 56 + 12 = 68

- Q + R = 111 ? Q + 68 = 111 ? Q = 43

- P + T = 137 ? 56 + T = 137 ? T = 81

- Now S is between Q and P, so S = x where 43 < x < 56, pick S = 50

Let’s check U:

- S < U, P < U

- U < 69 ? so U = 67 (since R = 68, U < R)

- Final Order:

Q (43), S (50), P (56), U (67), R (68), T (81)

Sum Q + T: 43 + 81 = 124

So, Option 1: 124 is correct.

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- Q scored the lowest, 43 marks.

- S scored higher than Q but lower than P, 50 marks.

- P scored the third lowest, 56 marks.

- R, who is higher than P, got 68 marks (12 more than P).

- U is higher than S and P but lower than 69, so 67.

- T has the highest marks at 81 (higher than R).

- Q + R = 111 is satisfied.

- P + T = 137 is satisfied.

- Correct answer is: Option 1: 124