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Directions: In the given series a, b, c, d are positive integers that are given in terms of x, y, and any one of them.
20, a, b, c, d, 65
Set - 1.
x = HCF (2, 7)
y = z
z2 – 8z + 12 = 0 (smaller root)
Set - 2.
(a – 20) = x2 + y2
b = (x + 1)2 + y + a + 1
c = (x + 2)2 + y + b – 2
d = (x + 1)2 + y + c + 2
Find the value of "c" in given number series.
41
36
25
51
38
Sure, let's work through the problem:
- HCF Calculation:
- HCF of 2 and 7 is 1.
- So, \( x = 1 \).
- Smaller Root Calculation:
- The equation \( z^2 - 8z + 12 = 0 \) can be factored as \( (z - 6)(z - 2) = 0 \).
- Roots are 2 and 6.
- Smaller root is 2.
- So, \( y = 2 \).
- Set - 2 Calculations:
- \( a - 20 = x^2 + y^2 = 1 + 4 = 5 \rightarrow a = 25 \).
- \( b = (x + 1)^2 + y + a + 1 = 4 + 2 + 25 + 1 = 32 \).
- \( c = (x + 2)^2 + y + b - 2 = 9 + 2 + 32 - 2 = 41 \).
- \( d = (x + 1)^2 + y + c + 2 = 4 + 2 + 41 + 2 = 49 \).
- Conclusion:
- c = 41.
- Correct Option:
- Option 1: 41
Correct Answer: Option 1 - 41
By: Parvesh Mehta ProfileResourcesReport error
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