Explanation:

Let's break down the statements and the options:

- E has 3 friends. Out of these, 1 is male and 2 are female.

- E wrote 300 books. Divided equally among 3 friends, each gets 100 books.

- Each friend of E has 5 friends.

Now, if the female friends give 1 book more to each of their 5 friends than the male does, think:

- Let the male friend give x books to each.

- Then, each female gives (x+1) books to each of their 5 friends.

- Total books by male: 5x.

Total books by one female: 5(x+1).

- Since each friend receives all 100 books:

For male: 5x = 100 ? x = 20.

For female: 5(x+1) = 100 ? x+1 = 20 ? x = 19.

- This is not possible, as x cannot have two values at the same time. But let's see if the distribution can be assigned in another way.

- However, the question is about ways the females can distribute 1 more book to each of their friends than the male.

Ways:

- For each female (there are 2), the 5 friends can get the books in any order, but if each must get one more than the male's friends, it's fixed per person.

- However, the number of ways is permutations of distributing the books to the friends.

- For each female: ways = number of arrangements = 5! = 120.

- Total ways = for two females: nothing more to multiply, since the assignment is fixed, unless order matters between females.

- But if it's distribution to friends, and both females do independently, then it's 120 ways for each.

So, Option 2: 120 is correct.

Correct Answer:

- Option 2, 120