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If p + q + r = 15.
Quantity I: Maximum value of pqr, if p, q, r are positive integers.
Quantity II: Maximum value of pqr, if p, q, r ≥ -10.
QI > QII
QI < QII
QI ≤ QII
QI ≥ QII
Cannot be determined
- Quantity I considers maximizing \(pqr\) with the condition that \(p, q, r\) are positive integers.
- The best strategy is to distribute the sum \(p + q + r = 15\) as evenly as possible.
- A common choice is \(p = 5\), \(q = 5\), \(r = 5\). Thus, \(pqr = 5 \times 5 \times 5 = 125\).
- Quantity II allows \(p, q, r\) to include negative values, making them capable of much larger absolute values when negative.
- To maximize, using extreme values like \(p = 40\), \(q = -10\), \(r = -15\) gives \(pqr = 40 \times (-10) \times (-15) = 6000\).
- Answer: By comparing, \(125 < 6000\).
- Correct Answer: Option 2: QI < QII.
By: Parvesh Mehta ProfileResourcesReport error
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