Boats and Streams

Quantitative Aptitude (SBI-PO)

Title

45:30

Video Progress

8 of 24 completed

Notes Progress

5 of 15 completed

MCQs Progress

38 of 100 completed

Subjective Progress

8 of 20 completed

Continue to Next Topic

Indian Economy - Understanding the basics of Indian economic system

Next Topic

Download Solution PDF

Directions: Answer the questions based on the information given below

Seller 'A' and seller 'B' sold a certain number of 'wooden' and 'plastic' toys. The selling price of each 'wooden' toy that is sold by seller 'A' is equal to the selling price of each 'wooden' toy that is sold by seller 'B'. The selling price of each 'plastic' toy that is sold by seller 'A' is equal to the selling price of each 'plastic' toy that is sold by seller 'B'. The total unit sale of 'plastic' toys to 'wooden' toys by seller 'A' is in the ratio of 3 : 8 respectively. The ratio of the total number of 'wooden' toys sold by seller 'A' to that by seller 'B' is in the ratio of 2 : 3 respectively. The total number of toys sold by seller 'B' is 100. The number of 'plastic' toys sold by seller 'B' is equal to the number of 'wooden' toys sold by seller 'A'. The selling price of each 'wooden' toy is double the selling price of each 'plastic' toy and it is applicable for both the given sellers.

Boat 'P' and Boat 'Q' are travelling in two different rivers called 'A' and 'B' respectively. Downstream speeds of boat 'P' and boat 'Q' are in the ratio of 6 : 5 respectively. The upstream speed of boat 'P' is 8 km/hr less than the downstream speed of boat 'Q'. If boat 'P' can cover 160 km in upstream in 5 hours and it is given that river 'B' flows 2 km/hr faster than river 'A' then find the time taken by boat 'Q' to cover the same distance in upstream?

This questions was previously asked in

SBI PO Mains (30 Jan, 2023)

View All SBIPO Previous Year Papers

4 hours

6 hours

8 hours

10 hours

12 hours

Explanation:

- Seller A's ratio of plastic to wooden toys is 3:8. If the number of wooden toys sold by Seller A is W, then plastic toys are (3/8)W.

- Seller B sells 100 toys in total. Seller B's wooden to Seller A's wooden toys are in the ratio 3:2, so Seller B sells (3/2)W wooden toys. This means Seller B sells W plastic toys. Therefore, Seller A sells (3/8)W plastics = W, which implies W = 24, satisfying all conditions.

- The selling price of each wooden toy is double that of each plastic toy for both sellers.

- Boat P travels 160 km upstream in 5 hours, so its upstream speed is 32 km/hr.

- Boat Q's downstream is 32 + 8 = 40 km/hr (since P's upstream is 8 km/hr less).

- From the ratio, Boat P's downstream speed is 48 km/hr.

- If river B is 2 km/hr faster in flow, Boat Q’s net speed in the same distance upstream: Boat Q's river speed is 10 km/hr (because 48 - 40 = 8 + 2).

- Time for Boat Q to cover 160 km upstream = 160 / 20 = 8 hours.