Directions: Answer the questions based on the information given below
Seller 'A' and seller 'B' sold a certain number of 'wooden' and 'plastic' toys. The selling price of each 'wooden' toy that is sold by seller 'A' is equal to the selling price of each 'wooden' toy that is sold by seller 'B'. The selling price of each 'plastic' toy that is sold by seller 'A' is equal to the selling price of each 'plastic' toy that is sold by seller 'B'. The total unit sale of 'plastic' toys to 'wooden' toys by seller 'A' is in the ratio of 3 : 8 respectively. The ratio of the total number of 'wooden' toys sold by seller 'A' to that by seller 'B' is in the ratio of 2 : 3 respectively. The total number of toys sold by seller 'B' is 100. The number of 'plastic' toys sold by seller 'B' is equal to the number of 'wooden' toys sold by seller 'A'. The selling price of each 'wooden' toy is double the selling price of each 'plastic' toy and it is applicable for both the given sellers.
Find the difference between the total number of toys sold by seller 'A' to that by seller 'B'?
This questions was previously asked in
SBI PO Mains (30 Jan, 2023)
Explanation:
- Total number of toys seller 'B' sold: 100.
- Plastic to wooden toys ratio for seller 'A': 3 : 8.
- Ratio of wooden toys sold by 'A' to 'B': 2 : 3.
- Number of plastic toys sold by 'B' equals wooden toys sold by 'A'.
Let the number of wooden toys sold by seller 'A' be \(2x\) and by seller 'B' be \(3x\).
Plastic toys by 'A' is \(3/8\) of wooden toys, which is \((3/8) \times 2x = (3/4)x\).
Hence, \(2x + (3/4)x\) is the total for 'A'.
Seller 'B' sells \(100\) toys, and if wooden toys are \(3x\), the plastic toys are \(100 - 3x\).
Given number of plastic toys by 'B' equals wooden toys by 'A', we have \(100 - 3x = 2x\), thus \(100 = 5x\), hence \(x = 20\).
- Wooden toys by 'A': \(2x = 40\).
- Plastic toys by 'A': \((3/4)x = 15\).
Total toys by 'A': \(40 + 15 = 55\).
The difference in total toys sold: \(55 - 100 = -45\).
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By: Parvesh Mehta