send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A mixture of 189 litres that contain alcohol and water in the ratio of 5 : 4. Find the amount of pure alcohol added to the mixture, to get a new mixture containing alcohol and water in the ratio of 5 : 3.
27 litres
35 litres
32 litres
40 litres
None of these
- Original Mixture: It contains 189 litres with an alcohol to water ratio of 5:4.
- Alcohol in Original Mixture: The fraction of alcohol is 5/(5+4) = 5/9.
- Actual Alcohol Content: 189 * (5/9) = 105 litres.
- Water Content: 189 - 105 = 84 litres.
- New Ratio Required: Alcohol to water should be 5:3.
- Equation to Solve: Let x be the additional pure alcohol. Hence, (105 + x)/84 = 5/3.
- Solving: Cross-multiply and solve (105 + x) = (5/3) * 84.
- Calculate x: (5/3) * 84 = 140; therefore, 105 + x = 140, so x = 35 litres.
Option:2, 35 litres is the correct answer.
By: Parvesh Mehta ProfileResourcesReport error
Access to prime resources
New Courses