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The length of a rectangular field is 4 meter more than its breadth. The perimeter of the field is 248 meter. If a 5 meter wide path is to be constructed outside of this field. Find the area of the path?
1340 m2
645 m2.
2 860 m2
1148 m2
None of these
- The perimeter of the rectangular field is given as 248 meters.
- If the field's breadth is \(b\), then its length is \(b + 4\) meters.
- Perimeter formula for a rectangle: \(2 \times (\text{length} + \text{breadth}) = 248\).
- This simplifies to \(2 \times (b + b + 4) = 248\).
- Solving this gives \(2 \times (2b + 4) = 248\) or \(4b + 8 = 248\).
- Solving, \(4b = 240\) or \(b = 60\). So, breadth = 60 meters, length = 64 meters.
- Adding a 5-meter-wide path around it increases both dimensions by 10 meters (5 meters each side).
- New dimensions: breadth \(= 70\), length \(= 74\).
- New area including path: \(70 \times 74 = 5180\) square meters.
- Original area of the field: \(60 \times 64 = 3840\) square meters.
- Area of the path: \(5180 - 3840 = 1340\) square meters.
Your final correct statement:
- Correct Answer: Option 1 - 1340 m²
By: Parvesh Mehta ProfileResourcesReport error
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